The M1/E2 mixing ratio δ = sqr(TE2/TM1),

where the T is the transition probability [1/sec].

In history, the sign convention of the mixing ratio is NOT consistent.

Here I only use + sign.

TE2 = (1/sec).

TM1 = (1/sec).

arctan(δ) = (deg.)

δ =

The numerical expressions for the E2 and M1 single-particle Weisskopf estimates:

( only a rough estimation.)

A = (atomic mass)

E_{γ} = (in the unit of MeV)

TE2 = (1/sec).

TM1 = (1/sec).

-----------------------------------

TE1 = (1/sec).

TM2 = (1/sec).

Formulae:

$\textrm{TE2}$ = $7.2 \times 10^{7} \,\, (E_{\gamma})^5 A^{4/3}$

$\textrm{TM1}$ = $5.6 \times 10^{13} (E_{\gamma})^3$

$\textrm{TE1}$ = $1.0 \times 10^{14} (E_{\gamma})^3 A^{2/3}$

$\textrm{TM2}$ = $2.2 \times 10^{7} \,\, (E_{\gamma})^5 A^{2/3}$

Note: M2 transitions are generally inhibited compared to the Weisskopf estimate by a factor at least 10, according to D. Kurath and R.D. Lawson, Phys, ReV. 161, 915.

Useful resources: slides from 2013 postgraduate summer school.